| === compdoc_ is now known as compdoc | ||
| === miguel is now known as Guest44856 | ||
| skylite | why does sudo -u someuser bash -c "for i in {1..5}; do echo $i; done" not work the way expected? | 00:47 |
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| jerichowasahoax | skylite: because you didn't escape the $ | 00:57 |
| jerichowasahoax | skylite: so $i was expanded when the command line was processed, and since $i was empty then, you ended up with "for i in {1..5}; do echo ''; done" | 00:58 |
| skylite | but it prints 5 five times | 00:58 |
| jerichowasahoax | because of your for loop, yes | 00:59 |
| jerichowasahoax | it set $i to 1, then ran an empty echo line, then set $i to 2, etc etc | 00:59 |
| skylite | I dont really see how escaping solves this issue | 01:01 |
| jerichowasahoax | it prevents $i from being expanded when processing the inital command line | 01:02 |
| skylite | I tought escaping makes the shell interpret $ as a character and not as a variable sign | 01:02 |
| jerichowasahoax | yes | 01:02 |
| jerichowasahoax | the shell you're typing your command line into no longer interprets that as a variable to expand | 01:02 |
| jerichowasahoax | so, it passes the string $i as a command line parameter | 01:03 |
| skylite | I see | 01:03 |
| jerichowasahoax | and THAT shell that you're running sees "$i", and goes "oh, a variable!" | 01:03 |
| jerichowasahoax | remember, there's two shells here | 01:03 |
| jerichowasahoax | the "bash -c" in your command line, and the shell you're running that command line in | 01:03 |
| skylite | jerichowasahoax: thx | 01:06 |
| jerichowasahoax | skylite: np | 01:15 |
| ShriHari | hello | 05:38 |
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